作者：OrkhanJafarov译者：FrontendXiaozhi来源：dev今天我们来学习如何在元素的第一个元素上添加元素。1.Array.unshift()letfruits=["Apple","Banana","Mango"];fruits.unshift("Orange");console.log(fruits);//打印["Orange","Apple","Banana","Mango"]fruits.unshift("Guava","Papaya");console.log(fruits);//打印["Guava","Papaya","Orange","Apple","Banana","Mango"]2.使用扩展运算符(...)varfruits=["Apple","Banana","Mango"];varmoreFruits=["Orange",...fruits];console.log(moreFruits);//打印["Orange","Apple","Banana","Mango"]varsomeoMoreFruits=["Guava","Papaya",...moreFruits];console.log(someoMoreFruits);//打印["Guava","Papaya","Orange","Apple","Banana","Mango"]console.log(fruits);//打印["Apple",《香蕉》、《芒果》]3、使用Array.concat()我们也可以使用concat()方法在开头连接两个（或更多）数组。varfruits=["Apple","Banana","Mango"];varmoreFruits=["Orange"];varsomeMoreFruits=["Guava","Papaya"];varallFruits=someoMoreFruits。concat(moreFruits,fruits);console.log(allFruits);//打印["Guava","Papaya","Orange","Apple","Banana","Mango"]End~我是小智，我是去洗碗了，下期见~代码部署后可能存在的bug我们无法实时得知。之后为了解决这些bug，我们花了很多时间在日志调试上。顺便推荐一个好用的bug监控工具Fundebug。原文：https://codingnconcepts.com/j...每周更新交流文章。可以微信搜索“大千世界”阅读即时更新（比博文早一两篇）。这篇文章在GitHubhttps://github.com/qq449245884/xiaozhi已经收录，整理了很多我的文档。欢迎star和改进。可以参考考点面试。另外，关注公众号，后台会回复福利，看到福利就知道了。
