C语言中如何初始化多维Char数组？我正在尝试将一些代码从C#转换为C，以便将其刻录到微控制器上。有人可以告诉我如何将C#中的二维字符串数组转换为C中的内容吗？我的C#代码如下所示：string[,]DirectionPosition={{"00","10","","01",""},{"01","11","","02","00"},{"02","12","","03","01"},{"03","13","","04","02"},{"04","14","","","03"},{"10","20","00","11",""},{"11","21","01","12","10"},{"12","22","02","13","11"},....{"44","","34","","43"},};而且，我将如何访问该元素？在C#中，如果我想要第三行的第二个元素，它只是DirectionPosition[2,1]，但是当C中没有字符串时，一个更少的二维字符串数组是什么？charDirectionPosition[][5][3]={{"00","10","","01",""},{"01","11","","02","00"},{"02","12","","03","01"},{"03","13","","04","02"},{"04","14","","","03"},{"10","20","00","11",""},{"11","21","01","12","10"},{"12","22","02","13","11"},....{"44","","34","","43"},};C没有内置的字符串类，你必须使用字符数组。您还可以使用指向char的指针。最简单的方法是像这样使用字符指针：char*DirectionPosition[9][5]={{"00","10","","01",""},{"01","11","","02","00"},{"02","12","","03","01"},{"03","13","","04","02"},{"04","14","","","03"},{"10","20","00","11",""},{"11","21","01","12","10"},{"12","22","02","13","11"},{"44","","34","","43"}};第一行中的元素“10”被引用为DirectionPosition[0][1]（从零开始，第一个索引是行，第二个是列）。我建议确定字符串的最大长度和每行的最大字符串数，并告诉编译器，例如：typedefcharstring[3];typedef字符串s5[5]；s5DirectionPosition[]={{"00","10","","01",""},{"01","11","","02","00"},{"02","12","","03","01"},{"03","13","","04","02"},{"04","14","","","03"},{"10","20","00","11",""},{"11","21","01","12","10"},{"12","22","02","13","11"},{"44","","34","","43"},};现在DirectionPosition[2][1]&c将允许您访问特定的字符串。有一个稍微简单一点的方法，不需要所有额外的括号：以上是C#学习教程：HowtoinitializeamultidimensionalChararrayinC?分享的所有内容，如果对你有用，需要了解更多C#学习教程，希望大家多多关注——#includeintmain(intargc,char**argv){charDirectionPosition[][5][3]={"00","10","","01","","01","11","","02","00","02","12","","03","01","03","13","","04","02","04","14","","","03","10","20","00","11","","11","21","01","12","10","12","22","02","13","11","44","","34","","43"};printf("dp[1][1]==%sn",DirectionPosition[1][1]);printf("dp[1][2]==%sn",DirectionPosition[1][2]);printf("dp[1][3]==%sn",DirectionPosition[1][3]);返回;}本文收集自网络，不代表立场。如涉及侵权，请点击右侧联系管理员删除。如需转载请注明出处：
