给定两个数组，编写一个函数来计算交集，返回的数组不重复

//方法一：constintersection=(arr,arr1)=>{letobj={},res=[];arr.forEach(item=>{obj[item]=true;})arr1.forEach(item=>{if(obj[item]){res.push(item)obj[item]=false}})返回res}//方法二：constintersection=(arr,arr1)=>[...newSet(arr.filter(item=>arr1.includes(item)))]