LeetCode解答｜7.整数反转

/***@param{number}x*@return{number}*/varreverse=function(x){letres=0;while(x!=0){res=res*10+(x%10);//高亮x=~~(x/10);如果(resMath.pow(2,31)-1){返回0;}}if(x>=0){返回res;}返回-res;};