-javaScript-数组去重方法总结（2017）

现在需要对以下数组进行去重[1,2,3,3,3,'0','1','2','test','repeat','重复',NaN,NaN,false,false];方法一：ES6Set()letarr=[1,2,3,3,3,'0','1','2','Test','Repeat','Repeat',NaN,NaN,false，错误的];arr=[...新设置（arr）]；//去重后：[1,2,3,'0','1','2','Test','Repeat',NaN,false]Set是ES6新增的集合，取值收藏中不再赘述。...运算符会将可遍历对象转换为数组。方法二：使用对象letarr=[1,2,3,3,3,'0','1','2','test','repeat','repeat',NaN,NaN,false,false];letobj={};lettemp=[];for(leti=0;i0){if(Object.is(arr[0],arr[1])){//Object.is()用于比较2个值，比===更可靠例如，Object.is(NaN,NaN)会判断为真arr.shift();}else{temp.push(arr.shift());}}//该方法会清空原数组，可以复制一个数组进行操作console.log(temp)//去重后:['0',1,'1','2',2,3,NaN,false,'test','repeat']方法四：forinletarr=[1,2,3,3,3,'0','1','2','test','repeat','repeat',NaN,NaN,false,false];lettemp=[];for(leti=0;i